Label the bonds between xenon and fluorine using the σ and π notation followed by the type of overlapping orbitals.

Answer:

σ: Xe( Sp3d2) - F(p)

Explanation:

Step one: write the ground state configuration and the excited state configuration of the xenon atom.

Ground state= [Kr] 5s2. 4d10. 5p6.

The Sp3d2 hybrid will be the impaired electrons will bond with the fluorine atom.

For pi, π bonding we have;

Xe(Sp3d2) - F(p), Xe(sp3d) - F(s),

Xe(sp3d) - F(p) and Xe(Sp3d2) - F(s).

For sigma, σ bonding we have;

Xe(sp3d) - F(s) and Xe(Sp3d2) - F(p).

Because the participation in hybridization involves only p orbital electron, in the pi bonding scheme;Xe(sp3d) - F(s), and Xe(Sp3d2) - F(s) are ruled out. Also, in the sigma bonding scheme; Xe(sp3d) - F(s) is ruled out.

Hence, we have;

σ: Xe( Sp3d2) - F(p).