Question
Solve
f(x)=15(0.2)^x
f(x)=40+1^x
X=years
Solve for x.
Thanks to whoever answers and best answer will be brainiest!
f(x)=15(0.2)^x
f(x)=40+1^x
X=years
Solve for x.
Thanks to whoever answers and best answer will be brainiest!
Asked by: USER2871
145 Viewed
145 Answers
Answer (145)
[tex]f(x)=15\cdot0.2^x\\
0.2^x=\dfrac{f(x)}{15}\\
x=\log_{0.2}\dfrac{f(x)}{15}\\\\\\
f(x)=40+1^x\\
1^x=f(x)-40\\
x=\log_1(f(x)-40)[/tex]