Question
Suma a patru numere consecutive impare este 880. Sa se afle numerele.
Dau cel mai bun raspuns
Dau cel mai bun raspuns
Asked by: USER8278
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100 Answers
Answer (100)
a |----------|
b |----------|2|
c |----------|2|2|
d |----------|2|2|2| } 880.
880- (2+2+2+2+2+2)=880-12=868 ( 4 segmente egale cu a)
868 : 4 = 217 (a)
217 + 2= 219 (b)
217 +2+2 = 221 (c)
217 + 2+2+2 = 223 (d)
Proba : 217+219+221+223=880.
b |----------|2|
c |----------|2|2|
d |----------|2|2|2| } 880.
880- (2+2+2+2+2+2)=880-12=868 ( 4 segmente egale cu a)
868 : 4 = 217 (a)
217 + 2= 219 (b)
217 +2+2 = 221 (c)
217 + 2+2+2 = 223 (d)
Proba : 217+219+221+223=880.