Question
3a + 3. En factorisation
a aux carré -16
4(x-3) +x(x-3)
4x aux carré -24x +36
16a exposant 4 -1
???????
a aux carré -16
4(x-3) +x(x-3)
4x aux carré -24x +36
16a exposant 4 -1
???????
Asked by: USER6983
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146 Answers
Answer (146)
3a + 3. En factorisation
= 3(a+1)
a aux carré -16 identité remarquable a²-b²
= a²-4²
= (a+4)(a-4)
4(x-3) +x(x-3)
on met en facteur x-3
(x-3)(4+x)
4x aux carré -24x +36
identité remarquable (a-b)²
= (2x)²-2*2*6+6²
= (2x-6)²
16a exposant 4 -1 identité remarquable a²-b²
= (4a)²-1²
= (4a²+1)(4a²-1)
= (4a²+1)((2a)²-1²)
= (4a²+1)(2a+1)(2a-1)
= 3(a+1)
a aux carré -16 identité remarquable a²-b²
= a²-4²
= (a+4)(a-4)
4(x-3) +x(x-3)
on met en facteur x-3
(x-3)(4+x)
4x aux carré -24x +36
identité remarquable (a-b)²
= (2x)²-2*2*6+6²
= (2x-6)²
16a exposant 4 -1 identité remarquable a²-b²
= (4a)²-1²
= (4a²+1)(4a²-1)
= (4a²+1)((2a)²-1²)
= (4a²+1)(2a+1)(2a-1)