Zincul in reactie cu o solutie de HCL formeaza clorura de ZN SI H!
1)Masa solutiei de HCL 10% care reactioneaza cu 260gZN ce contine 10% impuritati!
2)Masa de sare care formeaza in reactia de la 1 !!!
Va rog ajutati-ma!!!
50 DE PUNCTE!

Zn + 2HCl --> ZnCl2 + H2↑

1) 10% impuritati ==> 90% pur

p=mpur/mipur*100==>mpur=p*mipur/100=90*260/100=234g Zn pur

65g Zn......73g HCl.......136g ZnCl2.....2gH2
234g..........x=262.8g.....y=489.6g

Cp=md/ms*100==>ms=md*100/Cp=262.8*100/10=2628g sol.HCl

2) msare=489.6

n=m/M=489.6/136=3.6 moli sare

MZn=65g/mol

MHCl=36.5g/mol

MZnCl2=136g/mol